Question 1157991

Drawn in a circle whose radius is 12 cm, chord AB is 16 cm long. Calculate the angular
size of minor arc AB.
<pre>With center O, and altitude OD drawn from center to chord, we get cos &#8737OAD = {{{matrix(1,5, A/H, "=", 8/12, "=", 48.19^o)}}}
&#8737OBD also = 48.19<sup>o</sup>
Therefore, central &#8737AOB = 180 - 2(48.19<sup>o</sup>) = 180 - 96.38<sup>o</sup> = 83.62<sup>o</sup>
From this, we can see that {{{highlight_green(matrix(1,6, Minor, arc, AB, also, measures, 83.62^o))}}}
That's ALL!!