Question 1157927
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Determine {{{(r+s)(s+t)(r+t)}}}, if r, s, and t are the three real roots of the polynomial {{{x^3+9x^2-9x-8}}}.
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<pre>
(r+s)(s+t)(r+t) = ((r + s + t)-t) * ((s + t + r) - r) * ((r + t + s) - s) =


    In the last three factors, replace  r+s+t by -9 (the value opposite to the coefficient at x^2).
    Then continue the equality


= (-9-t)*(-9-r)*(-9-s) = -(9+t)*(9+r)*(9+s) = 

= -(81 + 9t + 9r + tr)*(9+s) = -(729 + 81t + 81r + 9tr + 81s + 9ts + 9rs + trs) = 

= -(729 + 81*(t + r + s) + 9*(tr + ts + rs) + trs) = 


    In the last expression, replace  (t+r+s) by -9 (the value opposite to the coefficient at x^2);
    
    replace  (tr + ts + rs) by -9 (the value of the coefficient at x),

    and replace trs by 8 (the value opposite to the coefficient at the constant term of the polynomial, by Vieta's theorem).  


    You can continue then in this way


= -(729 + 81*(-9) + 9*(-9) + 8) = 73.     <U>ANSWER</U>
</pre>

Solved.