Question 1157840

7.

{{{a[n]=3^(n-1)}}}


1st term, {{{n=1}}}=>{{{a[1]=3^(1-1)}}}=>{{{a[1]=3^0}}}=>{{{a[1]=1}}}

2nd term, {{{n=2}}}=>{{{a[2]=3^(2-1)}}}=>{{{a[2]=3^1}}}=>{{{a[2]=3}}}

3rd term, {{{n=3}}}=>{{{a[3]=3^(3-1)}}}=>{{{a[3]=3^2}}}=>{{{a[3]=9}}}

4th term, {{{n=4}}}=>{{{a[4]=3^(4-1)}}}=>{{{a[4]=3^3}}}=>{{{a[4]=27}}}

5th term, {{{n=5}}}=>{{{a[5]=3^(5-1)}}}=>{{{a[5]=3^4}}}=>{{{a[5]=81}}}

8th term, {{{n=8}}}=>{{{a[8]=3^(8-1)}}}=>{{{a[8]=3^7}}}=>{{{a[8]=2187}}}



8.

{{{a[n]=2(1/4)^(n-1)}}}


1st term, {{{n=1}}}=>{{{a[1]=2(1/4)^(1-1)}}}=>{{{a[1]=2(1/4)^0}}}=>{{{a[1]=2*1}}}=>{{{a[1]=2}}}

2nd term, {{{n=2}}}=>{{{a[2]=2(1/4)^(2-1)}}}=>{{{a[2]=2(1/4)^1}}}=>{{{a[2]=2/4}}}=>{{{a[2]=1/2}}}

3rd term, {{{n=3}}}=>{{{a[3]=2(1/4)^(3-1)}}}=>{{{a[3]=2(1/4)^2}}}=>{{{a[3]=2(1/16)}}}=>{{{a[3]=1/8}}}

4th term, {{{n=4}}}=>{{{a[4]=2(1/4)^(4-1)}}}=>{{{a[4]=2(1/4)^3}}}=>{{{a[4]=2(1/64)}}}=>{{{a[4]=1/32}}}

5th term, {{{n=5}}}=>{{{a[5]=2(1/4)^(5-1)}}}=>{{{a[5]=2(1/4)^4}}}=>{{{a[5]=2(1/256)}}}=>{{{a[5]=1/128}}}

8th term, {{{n=8}}}=>{{{a[8]=2(1/4)^(8-1)}}}=>{{{a[8]=2(1/4)^7}}}=>{{{a[8]=2(1/16384)}}}=>{{{a[8]=1/8192}}}