Question 1157817
Let the numerator be x. The fraction is {{{x/2x+4}}}. The fraction {{{(x-6)/(2x-2)}}} is equal to 7/19. Suppose we let x-6=7 and 2x-2=19. We get x=13 and x=21/2, and both can not be true. Now suppose we let the numerator and denominator equal to 14 and 38 instead. Now we have x=20 and x=20. So the fraction is {{{20/44}}}.