Question 107264
I'm a little confused as to the problem.
"...the equation of this line (y = x+2) passing through the two points (-3, 6) and (3, 0)".
In the first place, the line given by the equation y = x+2 does not pass through the two given points (-3, 6) and (3, 0)!
We can find the equation that does pass through the two ponts as follows:
Starting with the slope-intercept form: y = mx+b, we'll first find the slope, m, using the formula: {{{m = (y[2]-y[1])/(x[2]-x[1])}}} 
{{{m = (0-6)/3-(-3))}}}
{{{m = -6/6}}}
{{{m = -1}}} so now we can write:
{{{y = (-1)x+b}}} Now we need to find the value of b.  We do this by substituting the x- and y-coordinates of either one of the two given points into this equation and solving for b. Let's choose the second point (3, 0).
{{{0 = (-1)(3)+b}}} Simplify.
{{{0 = -3+b}}} Add 3 to both sides.
{{{3 = b}}} Now we can write the final equation:
{{{y = -x+3}}}