Question 1157796
Because there are 9 letters, there are 9! ways to do it, right? However, there are 4 s's and 3 a's that we have to account for. There are 4! and 3! ways to arrange the s's and a's, respectively. So there are actually {{{9!/4!3!}}} ways to arrange the letters. Simplifying, we get <br/> {{{9!/4!3!=(9*8*7*6*5*4*3*2*1)/(4*3*2*1)(3*2*1)= (9*8*7*6*5*cross(4*3*2*1))/cross((4*3*2*1))(3*2*1)=(9*8*7*6*5)/(3*2*1)=(9*8*7*6*5)/6=(9*8*7*cross(6)*5)/cross(6)=9*8*7*5=9*40*7=40*63=(63*4)*10=252*10=highlight(highlight_green(highlight(2520)))}}}.