Question 107235
Given:
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{{{(x^2)/(x- 3)- (9)/(x- 3)}}}
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Since the two fractions have the same denominator, their numerators can be combined
over the common denominator. The result is:
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{{{(x^2 - 9)/(x-3)}}}
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But the numerator is the difference of two squares. Therefore it can be factored according
to the following form:
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{{{A^2 - B^2 = (A + B)*(A - B)}}}
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In this case A = x and B = 3. So applying this factoring rule, we transform the problem to:
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{{{(x^2 - 9)/(x-3)= ((x - 3)*(x + 3))/(x - 3) =((cross(x-3))*(x + 3))/cross(x - 3)}}}
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After the above cancellation of the term in the numerator that is common with the term in
the denominator, the equivalent value of original expression is reduced to {{{x+3}}}.
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So the answer to this problem is {{{x+3}}} is the simplest form of the given problem.
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Hope this helps you to understand the problem.
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