Question 1157691
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Each rectangle is 1/4 wide; the values at the right endpoints are
1/(5/4) = 4/5
1/(6/4) = 2/3
1/(7/4) = 4/7
1/(8/4) = 1/2<br>
estimated area = {{{(1/4)(4/5+2/3+4/7+1/2) = 533/840}}} = 0.6345238 to 7 decimal places.<br>
The function is decreasing on the given interval; using right endpoints will result in an underestimate of the area.<br>
That is easily confirmed, since the area under the curve 1/x from 1 to 2 is ln(2) = 0.6931472<br>