Question 1157654
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*[tex \Large a_{n+1}\  =\ a_n\ +\ n^2]


You are looking for the 6th and 7th terms.  So if *[tex \Large n\ +\ 1] is 6, *[tex \Large n] is 5.  *[tex \Large a_5\ =\ 32] and *[tex \Large 5^2\ =\ 25] so *[tex \Large a_6\ =\ 32\ +\ 25\ =\ 57]. You can figure out the 7th term for yourself.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \