Question 1157612
How do you express (x^2-3)^3-(2-2x^2)^2+3 (x^2-3) 
in the form 
(x^4+Ax^2+B)(x^2+C) where A, B and C are integers?
<pre>
{{{(x^2-3)^3-(2-2x^2)^2+3(x^2-3)=(x^4+Ax^2+B)(x^2+C)}}}

After multiplying both sides out,

{{{x^6-13x^4+38x^2-40=x^6+(A+C)x^4+(AC+B)+BC}}}

and equating coefficients, we get this system of equations.

{{{system(A+C=13,AC+B=38,BC=-40)}}}

But that system does not have integer solutions. 

So your problem is impossible. Did you copy something wrong?

Edwin</pre>