Question 1157466
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P(at least one man) = 1 - P(no men) = 1-P(3 women)<br>
P(3 women and no men) = (C(4,3)*C(5,0))/C(9,3) = (4*1).84 = 4/84 = 1/21<br>
P(at least one man) = 1-1/21 = 20/21<br>
You can get practice calculating probabilities like this by finding the probabilities of choosing 1, 2, or 3 men.<br>
P(1 man) = (C(4,2)*C(5,1))/C(9,3) = (6*5)/84 = 30/84
P(2 men) = (C(4,1)*C(5,2))/C(9,3) = (4*10)/84 = 40/84
P(3 men) = (C(4,0)*C(5,3))/C(9,3) = (1*10)/84 = 10/84<br>
The sum of the probabilities is (4+30+40+10)/84 = 1.<br>