Question 1157320

Please help me solve this:

log(x^2 + 11x + 8) - log(x + 1) = 1 

thank you!
<pre>{{{matrix(1,3, log ((x^2 + 11x + 8)) - log ((x + 1)), "=", 1)}}}
{{{matrix(1,3, log (((x^2 + 11x + 8)/(x + 1))), "=", 1)}}}
{{{matrix(1,3, (x^2 + 11x + 8)/(x + 1), "=", 10^1)}}} ----- Converting to EXPONENTIAL form
{{{matrix(1,3, x^2 + 11x + 8, "=", 10(x + 1))}}} ------- Cross-multiplying
{{{matrix(1,3, x^2 + 11x - 10x + 8 - 10, "=", 0)}}}
{{{matrix(1,3, x^2 + x - 2, "=", 0)}}} 
(x - 1)(x + 2) = 0
{{{highlight_green(matrix(1,3, x, "=", 1))}}}            OR             x = - 2 (ignore)
Anyone who tells you otherwise is WRONG and they serve no purpose than to confuse you!