Question 1157282
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<pre>

In the denominator, you see {{{sqrt(x^2+x - 2)}}}.


In order for you will be able to take the square of a number, this number MUST be non-negative.


So, you first need to solve this inequality

    {{{x^2+x-2}}} >= 0.


Factor left side

    {{{(x-1)*(x+2)}}} >=0.


Either both factor should be negative, or both factors should be positive.


It gives you the solution set  x <= -2  or  x >= 1.


Also, x = -2 makes the denominator equal to zero, as well as the value x = 1.


Therefore, you must exclude them from the domain.


Finally, the domain is the union of two open intervals  (-oo,-2) U (1,oo).    <U>ANSWER</U>
</pre>

Solved.


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The "solution" by @josgarithmetic is WRONG.


Simply ignore it for your safety.