Question 1157265
Accept if 0 or 1 syringes are defective
probability 0 are defective is 0.99^12=0.8864
probability 1 is defective is 12*0.01*0.99^11=0.1074
The sum is 0.9938 or 0.994 probably of being accepted

np is mean or 12*0.01=0.12 syringes
variance is np(1-p) or .12*.99=.1188
sd is sqrt(V)=0.347 syringes  ANSWER