Question 1157276
This is like a two-part mixture problem.
d, how many dimes
23-d, how many nickels


{{{10d+5(23-d)=120}}}

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{{{2d+(23-d)=24}}}

{{{2d-d=24-23}}}

{{{highlight(d=1)}}}-----------------------one dime.

{{{highlight(22)}}}{{{nickels}}}------------------twenty-two nickels