Question 1157224
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Let x be the square of the first number, and let y be the square of the seconf number.

Then from the condition, you have these two equations


     x - y =  8     (1)

    3x + y = 28     (2)


Add the equations. You get


    4x = 8 + 28 = 36.   Hence, x = 36/4 = 9.  The first number is  {{{sqrt(9)}}} = +/- 3.


Next, substitute x= 9 into the first equation. You will get

    9 - y = 8,  y = 9 - 8 = 1;  hence,  the second number is  {{{sqrt(1)}}} = +/- 1.


<U>ANSWER</U>.  There are 4 pairs of the numbers (first,second) = (3,1),  (3,-1), (-3,1)  and  (-3,-1).
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Solved.