Question 1157127
Ho: pulse is 72
Ha: it isn't.
alpha=0.05 P{reject Ho|Ho true}
test stat is a tdf=25, 0.975)=(x bar- mean)/sigma/sqrt (n)
reject if |t|>2.06
calculation t=(70-72)/9.85/sqrt(26)
=-2*sqrt(26)/9.85
=-1.035
I get 1 sided p value of 0.15, or 2 -sided of 0.30

I don't see where the p-value of 0.132 comes from with these data. In that instance and what is shown here, one fails to reject the null hypothesis and says there is insufficient evidence to conclude the pulse rate is different.  We could have obtained a result by chance this great or greater with 30% probability.

The 95% CI is t0.975 df=25*s/sqrt(n) for a half interval.  That is 3.98
This is added or subtracted from the mean

(66.02, 73.98) is the interval, and because 72 is in the interval, we can conclude with 95% confidence that the true pulse of the sample of men, which will never be completely known, is not different from 72.