Question 1157108
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Tea worth $4.10 per pound is to be mixed with tea worth $4.90 per pound.
How many pounds of each should be used to obtain 25lb of a blend worth
$4.40 per pound?
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Tea worth $L per pound is to be mixed with tea worth $H per pound.
How many pounds of each should be used to obtain M lb of a blend worth
$T per pound?
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v pounds of the H dollars per pound ingredient
M-v pounds of the L dollars per pound ingredient


{{{Hv+L(M-v)=TM}}}
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{{{(H-L)v+LM=TM}}}
{{{(H-L)v=TM-LM}}}
{{{highlight(v=M((T-L)/(H-L)))}}}
Substitute the given values.


{{{v=25((4.4-4.1)/(4.9-4.1))}}}

{{{v=25((0.3)/(0.8))}}}


{{{v=highlight(9.375*pounds)}}}, the $4.9 per pound tea
(9 pounds 6 ounces)


{{{M-v=highlight(15.625*pounds)}}}, the $4.1 per pound tea
(15 pounds 10 ounces)