Question 1156968
P(A) = probability of getting 3 on a throw of dice
P(A) = 1/6

P(B) = probability of getting a 3 from a pack of card
P(B) = 4/52  ( since there are 4 3s in pack of 52 cards) 

Probability of both the events happening together
 = P(A) × P (B)
= {{{1/6 * 4/52}}}
= {{{1/78}}}