Question 1156960
{{{(x^2-3x)^2-3(x^2-3x)=x^2-3x}}}

.

.

{{{x(x^3-6x^2+5x+12)=0}}}

.

.
{{{x(x+1)(x-3)(x-4)=0}}}


Values which should work are -1, 0, 3, 4.