Question 1156894
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Here is a quick non-algebraic way to solve two-part mixture problems like this.<br>
Picture the three percentages on a number line: 23, 35, and 39.  The target percentage 35 is 12/16 = 3/4 of the way from 23 to 39.<br>
That means 3/4 of the mixture must be the 39% sand.<br>
So the 6 pounds of 39% sand he is using is 3/4 of the mixture; the 23% sand is 1/4 of the mixture, which is 1/3 of 6 pounds, or 2 pounds.<br>
Answer B<br>