Question 1156841
Poisson with parameter 10.  counts, proportional to time, can be theoretically infinite
e^(-10)^10^5/5!=0.0378
at least 2 units, look at 1 unit and 0, get those probabilities and subtract from 1.
p(0)=e^(-10)=0.000045
p(1)=e^(-10)10*1/1!=0.00045
These two add to 0.0005
probability at least 2 is 0.9995