Question 1156639


if the length {{{L}}} of a rectangle is {{{7}}} inches longer than it is wide {{{W}}}, we have

{{{L=W+7}}}.....eq.1


if the perimeter is {{{38}}} inches, we have

{{{2(L+W)=38}}}

{{{L+W=38/2}}}

{{{L+W=19}}}......substitute {{{L}}} from eq.1

{{{W+7+W=19}}}

{{{2W=19-7}}}

{{{2W=12}}}

{{{W=6}}}

go to

{{{L=W+7}}}.....eq.1, ....substitute {{{W}}} 

{{{L=6+7}}}

{{{L=13}}}


 the dimensions of the rectangle are {{{13}}} by {{{6}}}