Question 1156594
Solve the equation. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)
log(x + 3) = 1 − log(x − 2)
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Do NOT enter (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)  What is the point of that?
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log(x + 3) = 1 − log(x − 2)


Assuming base 10:
log(x + 3) = log(10) − log(x − 2)
log(x+3) = log(10/(x-2))
x+3 = 10/(x-2)
x^2 + x - 6 = 10
x^2 + x - 16 = 0
*[invoke solve_quadratic_equation 1,1,-16]
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The negative solution gives a negative argument for the log, ignore it.
x =~ 3.5311
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