Question 1156495

One number is 3 times another. The sum of their reciprocals is 
16/3. Find the numbers.
<pre>Let the smaller number be S
Then the larger number is 3S
We then get: {{{matrix(1,3, 1/S + 1/(3S), "=", 16/3)}}}
3 + 1 = 16S ------ Multiplying by LCD, 3S
4 = 16S
{{{highlight_green(matrix(2,8, S, or, smaller, number, "=", 4/16, "=", 1/4, 3S, or, larger, number, "=", 3(1/4), "=", 3/4))}}}
The numbers are <b><u>NOT</b></u> 4 & 12.