Question 1156480



If {{{log(3,5)= a }}}

{{{ log(3 ,6)=b }}}=>  {{{log(3 ,2*3)=b}}} =>  {{{log(3 ,2)+log(3 ,3)=b}}}=>  {{{log(3 ,2)+1=b}}}=> {{{ log(3 ,2)=b-1}}}


express {{{log(3 ,20)}}} in terms of {{{a}}} and {{{b}}}

{{{log(3 ,20) =log(3 ,2^2*5) }}}

{{{log(3 ,20) =log(3 ,2^2)+log(3 ,5) }}}

{{{log(3 ,20) =2log(3 ,2)+log(3 ,5)}}} .......substitute {{{log(3 ,2)}}} and {{{log(3 ,5)}}} from equations above


{{{log(3 ,20) =2(b-1)+a}}}

{{{log(3 ,20) =a+2b-1}}}