Question 107088
let your three consecutive numbers be x , x+1 and x+2

the sum of these are x+(x+1)+(x+2) which simplifies to 3x+3
This is equal to 93 so 3x+3=93
minus 3 from both sides
3x+3-3=93-3
3x=90

divivde both sides by 3
x=30

The first integer is 30 so the following two are 31 and 32