Question 1156362
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The region will look like a filled in circle or disk with radius 6. The center is at (0,0). 


Points on the edge of the disk represent solutions to |z| = 6, while points inside the disk are solutions to |z| < 6. 


Assuming there isnt a line under the less than sign, then you'll have a dashed boundary to indicate points on the boundary do not count. If you want the boundary points to count, then you'll have to write {{{abs(z) <= 6}}}


Diagram:
<img src = "https://i.imgur.com/5SM46Hv.png">
The blue region is the solution to {{{abs(z) < 6}}}. The red dashed boundary is not part of {{{abs(z) < 6}}}.
The equation of the red boundary circle is {{{x^2+y^2 = 36}}}
The inequality for the blue region is {{{x^2+y^2 < 36}}}


Note: recall that for any complex number {{{z = a+bi}}}, the magnitude of the complex number is {{{abs(z) = sqrt(a^2+b^2)}}} (it might help to plot an example complex number on the xy plane, draw a right triangle, then apply the pythagorean theorem)




Similar problem:
<a href = "https://www.algebra.com/algebra/homework/complex/Complex_Numbers.faq.question.1156361.html">https://www.algebra.com/algebra/homework/complex/Complex_Numbers.faq.question.1156361.html</a>
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