Question 1156264
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The 14 foot width is the whole major axis; the 2 foot height is the semi-minor axis.  The equation (with the origin at the center of the arch at ground level) is<br>
{{{x^2/7^2+y^2/2^2 = 1}}}<br>
Substitute y=1 and solve for x.<br>
Then remember the question asks for the width between the TWO points where the height is 1; that is 2x -- not just x.<br>