Question 107075


   Let  the length of AC = L

    so, AB = L-9( since AB is 9 cm shorter than AC)

   and BC = L+3( since BC is 3cm longer than AC)

      Let the perimeter = P = 48
   
   so, AC + AB + BC = 48

     or L+(L-9)+(L+3)= 48

      OR L + L - 9 +L + 3 = 48 

       OR 3L - 9 + 3 = 48

       OR 3L - 6 = 48
 
       OR 3L = 48 + 6

        OR 3L = 54

         OR L = 54 / 3

         OR L = 18

        SO, AC = 18

        SO AB = AC - 9 

              = 18 - 9
              = 9

     AND BC = AC + 3

             = 18 + 3

              = 21

CHECK :

AC + BC + AB = 18 + 9 + 21 

             = 48