Question 1156320


{{{x+(1/3)y=5/12}}}.......eq.1...both sides multiply by {{{12}}}
{{{8x + 3y = 4}}}.......eq.2
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{{{12x+4y=5}}}.......eq.1......eq.1...both sides multiply by {{{2}}}
{{{8x + 3y = 4}}}.......eq.2......eq.1...both sides multiply by {{{3}}}
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{{{24x+8y=10}}}.......eq.1
{{{24x + 9y = 12}}}.......eq.2
---------------------------------------subtract eq.2 from eq.1

{{{24x+8y-24x - 9y=10-12}}}

{{{8y - 9y=-2}}}

 {{{- y=-2}}}..both sides multiply by {{{-1}}}

{{{y=2}}}

go to

{{{8x + 3y = 4}}}.......eq.2, substitute {{{y}}}

{{{8x + 3*2 = 4}}}

{{{8x + 6= 4}}}

{{{8x = 4-6}}}

{{{8x = -2}}}

{{{x = -2/8}}}

{{{x = -1/4}}}

solution: ({{{ -1/4}}},{{{2}}})