<PRE><B>Question 1156252</B>
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&lt;pre&gt;

(1)  Since there are three times as many man as women, 

         - the probability that the randomly chosen person is a man is  {{{3/4}}},  and

         - the probability that the randomly chosen person is a woman is  {{{1/4}}}.



     THEREFORE, the probability that three randomly selected persons all are the men is  P = {{{(3/4)^3}}} = {{{0.75^3}}} = 0.421875.



(2)  the probability that three randomly selected persons are (2 women and 1 men) is  P = {{{C[3]^2*(3/4)^1*(1/4)^2}}} = {{{3*(3/4)^1*(1/4)^2}}} = 0.14.
&lt;/pre&gt;

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The calculated numbers in the post by @Boreal are incorrect, so IGNORE it, for your safety.


He misread the problem.


He is so hurry that has no time to read the problem properly.



</PRE>