Question 1156275
rewrite as x^2-14x+y^2-48y=0
complete the squares for each
x^2-14x+49+y^2-48y+576=625, adding 625 to the right
(x-7)^2+(y-24)^2=25^2
This is a circle with center (7, 24) and radius 25
the minimum value of x is (7-25)=-18
{{{graph(300,300,-40,40,-40,40,24+sqrt(-(x-7)^2+625),24-sqrt(-(x-7)^2+625))}}}