Question 1156186
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1)  Amplitude is ALWAYS <U>positive</U> value and NEVER is negative value, by the definition.


    So, in this problem the amplitude is |-3| = 3.


        NOT  -3  (!) (!) (!)




2)  The parent function to measure the shift in this problem  IS NOT -3sin(4x) - 5, as @Mathlover MISTAKENLY thinks 

     and determines the phase shift incorrectly.


    To determine the shift, the given function should be presented wit POSITIVE amplitude

        -3sn(4x-pi) - 5 = 3sin(4x) - 5

    which shows that the phase shift is 0 (zero, ZERO) in this case.


See the plot below.



    {{{graph( 330, 330, -3, 7, -10, 2,
          -3*sin(4x-3.14)-5
)}}}


    Plot y = -3*sin(4x-3.14) - 5


Thus regarding the amplitude and the phase shift, the answers by @MathLower1 are incorrect.


Edwin correctly found the amplitude as positive 3, but regarding the phase shift, he dodged a direct answer.
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