Question 1156188
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With formal algebra... if it is required....<br>
x = # dimes
x+8 = # nickels<br>
{{{10x+5(x+8) = 145}}}<br>
Solve using basic algebra; I leave that to you.<br>
Informally....<br>
Count the "extra" 8 nickels first.  That is 40 cents; what is left is equal numbers of dimes and nickels, with a value of 145-40 = 105 cents.<br>
The value of one dime and one nickel is 15 cents; to make the remaining 105 cents, the number of dimes and nickels has to be 105/15 = 7.<br>
ANSWER: 7 dimes and 7+8=15 nickels<br>
CHECK: 7(10)+15(5) = 70+75 = 145<br>