Question 107064
Since {{{y=-3x/2+12}}} and {{{y=3x/2+2}}}, then,

{{{-3x/2+12=3x/2+2}}}
{{{2(-3x/2+12)=2(3x/2+2)}}}
{{{-3x+24=3x+4}}}
{{{3x+4=-3x+24}}}
{{{3x+3x+4=-3x+3x+24}}}
{{{6x+4=0+24}}}
{{{6x+4=24}}}
{{{6x+4-4=24-4}}}
{{{6x+0=20}}}
{{{6x=20}}}
{{{x=20/6=10/3}}}

Solving for y,

{{{y=-3x/2+12}}}
{{{y=-3(10/3)/2+12}}}
{{{y=-10/2+12}}}
{{{y=-5+12}}}
{{{y=7}}}


Solving this system graphically,

{{{graph(1000,1000,-20,20,-20,20,3x/2+2,-3x/2+12),
   grid(1/3)}}}



They intersect at ({{{10/3}}},7) therefore, both solutions are correct.


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