Question 1155991
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ln(x) is a monotonically increasing function: if A > B then ln(A) > ln(B), and vice versa.<br>
So {{{ln(x^2+x+2)}}} will have its minimum value when {{{x^2+x+2)}}} has its minimum value.  You can find the minimum value of {{{ln(x^2+x+2)}}} using your knowledge of quadratic functions.<br>
For the maximum value of {{{ln(x^2+x+2)}}}, simply evaluate it at the two given endpoints and see which is greater.<br>
Note also that, again since ln(x) is monotonic increasing, you can tell which endpoint gives the maximum value of {{{ln(x^2+x+2)}}} by finding on which endpoint the value of {{{x^2+x+2}}} is greater.<br>