Question 107049
You must get them in the standard form of ax^2+bx+c=0.
2x^2 - 5x = 3
2x^2-5x-3=0
a=2, b=-5, c=-3
.
2(x-5)^2 = 3
2(x^2-10x+25)=3
2x^2-20x+50-3=0
2x^2-20x+47=0
.
x^2 + 4x + 4 = 7
x^2+4x-3=0
.
I'll do two and you can do the rest.
Ed
*[invoke solve_quadratic_equation 2, -5, -3]
*[invoke solve_quadratic_equation 2, -20, 50]