Question 1155913
y varies as directly as the square of x ,{{{y=kx^2}}}



 y =75/8 when x =5,  {{{75/8=k*5^2}}}

{{{k=75/(8*25)}}}

{{{k=3/8}}}



The model equation is  {{{highlight_green(y=(3/8)x^2)}}}.



find y when x =2.

{{{y=(3/8)*2^2}}}

{{{y=3*4/(2*4)}}}

{{{y=3/2}}}, {{{done}}}.