Question 1155851
{{{system(v=16000pi=h*pi*r^2,c=pi*r^2*10+2pi*rh*8.64)}}}
with v for the volume, c for the cost.

{{{system(h=v/(pi*r^2),c=10pi*r^2+2*8.64pi(v/(pi*r)))}}}


{{{c=10pi*r^2+17.28v/r}}}


{{{c=10pi*r^2+(17.28)(16000)pi/r}}}

.

.

.