Question 1155822
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<pre>

If cube A is inscribed in sphere B, then the diameter of the sphere B is the length 

of the longest 3D-diagonal of the cube  {{{sqrt(4^2 + 4^2 + 4^2)}}} = {{{4*sqrt(3)}}}.



Since the sphere B is inscribed in cube C, the measure of the cube C edge is  {{{4*sqrt(3)}}}.



Hence, the volume of the cube C is  {{{(4*sqrt(3))^3}}} = {{{4^3*3(sqrt(3))}}} = {{{64*3*sqrt(3)}}} = {{{192*sqrt(3)}}}.    <U>ANSWER</U>
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Solved.