Question 1155752

{{{csc(x)+cos(x)cot(-x)}}}.......use identities: {{{csc(x)=1/sin(x)}}}, {{{cot(-x)=-cot(x)}}}, and {{{-cot(x)=-cos(x)/sin(x)}}}


={{{1/sin(x)+cos(x)(-(cos(x)/sin(x)))}}}


={{{1/sin(x)-cos(x)(cos(x)/sin(x))}}}


={{{1/sin(x)-cos^2(x)/sin(x)}}}


={{{(1-cos^2(x))/sin(x)}}}..........use identity {{{1-cos^2(x)=sin^2(x)}}}


={{{sin^2(x)/sin(x)}}}


={{{sin(x)}}}