Question 1155667
<pre>
8 books CHOOSE 3 =

8C3 =

{{{8!/(3!(8-3)!)}}}

{{{8!/(3!5!)}}}

{{{(8*7*6*5*4*3*2*1)/((3*2*1)(5*4*3*2*1))}}}

{{{(8*7*6*cross(5)*cross(4)*cross(3)*cross(2)*1)/((3*2*1)(cross(5)*cross(4)*cross(3)*cross(2)*1))}}}

{{{(8*7*6)/(3*2*1)}}}

{{{(8*7*cross(6))/(cross(3*2)*1)}}}

{{{8*7}}}

56

Edwin</pre>