Question 12486
{{{y = x^2 + 6x + 8}}}


This is a parabola, that opens upward.


The x-intercept (where  y=0), is at 
{{{0=x^2 + 6x + 8}}}
0= (x+2)(x+4)
x = -2, x= -4.


Y-intercept is where x=0.  
{{{ y = 0^2 +6*0 +8}}}
{{{y=8}}}


Line of symmetry is always halfway between the intercepts, which would be halfway between x=-2 and x= -4.  Line of symmetry is the line x= -3.


Graph looks like this:
{{{ graph(300, 300, -10, 10, -10, 10, x^2 + 6x +8) }}}


R^2 at SCC