Question 1155422

Find the critical points of the following function.
f(x)=2x^2-3x-5
<pre>There are 3 CRITICAL points of a parabola. They are:
1) the y-intercept (it's obvious that this is - 5)
2) the x-intercepts, if any [solving the equation for x, by setting f(x) = 0 will accomplish this task, and also, this equation can be FACTORED]
3) the VERTEX (this is found by determining the x-coordinate of the vertex, using the formula: {{{matrix(1,3, x, "=", - b/(2a))}}}, and then substituting this x-value into f(x)
   to get the y-coordinate of the vertex. These 2 coordinates will give you the vertex of the parabola, which by the way is a MINIMUM, as indicated by the
   leading coefficient being > 0. Alternatively, you can convert the function to the vertex form of a parabola, but that may be too much work!