Question 1155374
{{{Y=K+A*trig(B(x-h))}}} using the sine function for

amplitude:{{{A= -1}}}, 
translation: {{{K= -3}}}
phase shift {{{h=-pi/4}}} 
period :{{{2}}} => {{{T=2pi/B}}}=>{{{2=2pi/B}}}=>{{{2B=2pi}}}=>{{{B=pi}}}

{{{Y=-3-1*sin(pi(x-(-pi/4)))}}}
{{{Y=-3-sin(pi(x+pi/4))}}}


then the same type equation using the cosine function for

amplitude: {{{A=-2}}}
translation:{{{K= 1}}} 
phase shift {{{h=-pi}}}
period -??? I guess, I have to use-> periodicity of {{{cos (x )}}} which is {{{2pi}}} 

{{{P=2p}}} => {{{2pi=2pi/B}}}=>{{{B=2pi/pi}}}=>{{{B=1}}} 

{{{Y=1-2*cos(1(x-(-pi))) }}}
{{{Y=1-2cos(x+pi) }}}