Question 1155373
Write it as 14y^2-11y-3=0
the discriminate is sqrt (b^2-4ac)
b is 11, a is 14 and c is -3
sqrt(121+4*42) or sqrt(289)
this is a perfect square or 19., so as a positive discriminate there are no complex solutions, and as a perfect square, there are two rational roots.  They are 28/28 or 1 and -6/28 or -3/14

{{{graph(300,300,-5,5,-100,100,(14x^2-11x-3))}}}