Question 1155356
 Assume that adults have IQ scores that are normally distributed with a mean of 102.6 and a standard deviation of 21.2. Find the probability that a randomly selected adult has an IQ greater than 133.7. ​
z=x-mue/sd
z=133.7-102.6/21.2
z=31.1/21.2=1.466
0.9286
greater than 133.7 
probability 1-09286=0.0714
answer probability will be 0.0714