Question 1155306
I have a right angle triangle with 2 given sides. adjacent = 3 and the opposite = 5. I need to find a solution for the six trigonometric functions. The system is not accepting my solution of 5.8 for the hypotenuse, so I was wondering what I may have miscalculated.
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Hypotenuse = sqrt(3^2 + 5^2) = sqrt(34) =~ 5.831
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Maybe it's a matter of # of digits?
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a = short side = 3
b = 5
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A = angle opposite a, B opposite b
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6 functions of which angle?
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r = sqrt(34)
sin(A) = 3/r
cos(A) = 5/r
tan(A) = 3/5
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cot = 1/tan
sec = 1/cos
csc = 1/sin
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Adj = 3 and Opp = 5 is angle B.