Question 1155227


step I

draw a triangle with <A as 53 deg.
Step II
On AB and AC draw perpendicular bisectors

*[illustration circum_circle.png].

The point the intercept is the circum centre.

Step III

With this as centre draw a circle passing through all vertices

< a is intercepted by Arc BC

<BKC ia the central angle

< A is the inscribed angle

<BKC is twice angle A

The same argument holds good for B & C